What is the operating pressure of a hydraulic elevator with a gross weight of 1500 pounds and a plunger area of 15 square inches?

To determine the operating pressure of a hydraulic elevator, we can use the formula that relates weight, area, and pressure:

[ \text{Pressure} = \frac{\text{Weight}}{\text{Area}} ]

In this situation, we are given a gross weight of 1500 pounds and a plunger area of 15 square inches. Plugging these values into the equation gives:

[ \text{Pressure} = \frac{1500 \text{ lbs}}{15 \text{ in}^2} = 100 \text{ psi} ]

This calculation indicates that the operating pressure required to lift the elevator with that weight and plunger area is 100 psi.

Understanding the relationship between weight, area, and pressure is crucial for working with hydraulic systems in elevators. It is vital as it informs the design and functionality of the hydraulic system, ensuring it operates efficiently and safely under load conditions. As such, recognizing the implications of this calculation is key in advanced elevator topics, particularly for professionals dealing with maintenance or installation of hydraulic elevators.